3x^2-12+(x+2)=0

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Solution for 3x^2-12+(x+2)=0 equation:


Simplifying
3x2 + -12 + (x + 2) = 0

Reorder the terms:
3x2 + -12 + (2 + x) = 0

Remove parenthesis around (2 + x)
3x2 + -12 + 2 + x = 0

Reorder the terms:
-12 + 2 + x + 3x2 = 0

Combine like terms: -12 + 2 = -10
-10 + x + 3x2 = 0

Solving
-10 + x + 3x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-2 + -1x)(5 + -3x) = 0

Subproblem 1

Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(5 + -3x)' equal to zero and attempt to solve: Simplifying 5 + -3x = 0 Solving 5 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -3x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -3x = 0 + -5 -3x = 0 + -5 Combine like terms: 0 + -5 = -5 -3x = -5 Divide each side by '-3'. x = 1.666666667 Simplifying x = 1.666666667

Solution

x = {-2, 1.666666667}

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